[Insert an uncreative chat room title here]

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Re: [Insert an uncreative chat room title here]

Postby PuppetStrings » Thu Apr 23, 2015 12:26 am

RoyTheHero wrote:Yoooooo i think everyone already left,shit

I'm leaving right now. It's 3:26 AM and I wake up at 11 AM... bye
Sorry for the bad English >.<

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Re: [Insert an uncreative chat room title here]

Postby RoyTheHero » Thu Apr 23, 2015 12:27 am

Bai puppet
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Re: [Insert an uncreative chat room title here]

Postby katherine112 » Thu Apr 23, 2015 12:27 am

Imma go to ....yay school
i should be back soon
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Re: [Insert an uncreative chat room title here]

Postby RoyTheHero » Thu Apr 23, 2015 12:28 am

K,gl kathy
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Re: [Insert an uncreative chat room title here]

Postby katherine112 » Thu Apr 23, 2015 2:19 am

Soooo boring
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Re: [Insert an uncreative chat room title here]

Postby watchme1 » Thu Apr 23, 2015 3:06 am

g evening
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Re: [Insert an uncreative chat room title here]

Postby katherine112 » Thu Apr 23, 2015 3:26 am

watchme1 wrote:g evening


Hey!!! *hugs*
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Re: [Insert an uncreative chat room title here]

Postby watchme1 » Thu Apr 23, 2015 3:37 am

katherine112 wrote:
watchme1 wrote:g evening


Hey!!! *hugs*

*hugs back* How's the english morning going?
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Re: [Insert an uncreative chat room title here]

Postby katherine112 » Thu Apr 23, 2015 4:21 am

watchme1 wrote:
katherine112 wrote:
watchme1 wrote:g evening


Hey!!! *hugs*

*hugs back* How's the english morning going?


Controlled assesments.........waste of time
Plus being sleepy doesnt help :3
How are u ?

Oh come on people stop lurking
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Re: [Insert an uncreative chat room title here]

Postby JorJorBinks » Thu Apr 23, 2015 7:22 am

Hello everyone! Oh gosh battery at 1% again and school in 2 hours >.>
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Re: [Insert an uncreative chat room title here]

Postby milte345 » Thu Apr 23, 2015 7:26 am

JorJorBinks wrote:Hello everyone! Oh gosh battery at 1% again and school in 2 hours >.>

Seeya again never!
Maybe it'd be nice to stop thinking...
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Re: [Insert an uncreative chat room title here]

Postby katherine112 » Thu Apr 23, 2015 7:29 am

Have fun Jor ....
That is so nice of u to say milte xD
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Re: [Insert an uncreative chat room title here]

Postby totor » Thu Apr 23, 2015 10:02 am

evening ladies and gentlemen.
back from another day of tests
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Re: [Insert an uncreative chat room title here]

Postby Distortion » Thu Apr 23, 2015 1:14 pm

Im tired. ;w;
My math grade dropped again and i know im not going to be able to pass it by the end of the year, unless our teacher whips out extra credit which is unlikely. T^T

Hows everyone?
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Re: [Insert an uncreative chat room title here]

Postby totor » Thu Apr 23, 2015 1:18 pm

Distortion wrote:Im tired. ;w;
My math grade dropped again and i know im not going to be able to pass it by the end of the year, unless our teacher whips out extra credit which is unlikely. T^T

Hows everyone?


YOU CAN DO IT JUST BELIEVE IN YOURSELF AND REVISE!

and im fine :)
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Re: [Insert an uncreative chat room title here]

Postby PuppetStrings » Thu Apr 23, 2015 1:19 pm

Distortion wrote:Im tired. ;w;
My math grade dropped again and i know im not going to be able to pass it by the end of the year, unless our teacher whips out extra credit which is unlikely. T^T

Hows everyone?

What theme are you guy seeing? Maybe we could help you.
Also, nice. I had the Introduction to Scientific Thought test today and I think I won.
Sorry for the bad English >.<

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Re: [Insert an uncreative chat room title here]

Postby Distortion » Thu Apr 23, 2015 1:36 pm

Thanks for the support~
Right now we're doing slope, linear equations, and graphing. Which im not too good at. ;-;

Glad to see everyones doing well. c:
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Re: [Insert an uncreative chat room title here]

Postby PuppetStrings » Thu Apr 23, 2015 1:42 pm

Distortion wrote:Thanks for the support~
Right now we're doing slope, linear equations, and graphing. Which im not too good at. ;-;

Glad to see everyones doing well. c:

I don't know what's "slope" (I don't speak English perfectly) but the other 2 are easy. If you have problems with some exercise or something post it here and I'll help you if I'm online.
Sorry for the bad English >.<

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Re: [Insert an uncreative chat room title here]

Postby BirdyThePhoenix » Thu Apr 23, 2015 1:50 pm

*flops in*

Um...
why exactly are we talking about math?
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Re: [Insert an uncreative chat room title here]

Postby Distortion » Thu Apr 23, 2015 1:50 pm

birdyluv0 wrote:*flops in*

Um...
why exactly are we talking about math?

because im incapable of basic math skills
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Re: [Insert an uncreative chat room title here]

Postby PuppetStrings » Thu Apr 23, 2015 1:55 pm

Xanet734 wrote:
PuppetStrings wrote:
Distortion wrote:Thanks for the support~
Right now we're doing slope, linear equations, and graphing. Which im not too good at. ;-;

Glad to see everyones doing well. c:

I don't know what's "slope" (I don't speak English perfectly) but the other 2 are easy. If you have problems with some exercise or something post it here and I'll help you if I'm online.

Slope is essentially the angle of the line. It is Rise/Run. So if a line from point to point goes up 3 and over 3, then the slope is 3/3 or 1.

Ooooh. Inclination (here is "inclinación", which is translated as inclination).
Sorry for the bad English >.<

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Re: [Insert an uncreative chat room title here]

Postby BirdyThePhoenix » Thu Apr 23, 2015 2:02 pm

Yeah, yeah, let's talk about math.

How do you find the vertex on a parabola?
Well...
Okay, let's not get into this.
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Re: [Insert an uncreative chat room title here]

Postby totor » Thu Apr 23, 2015 2:08 pm

linear fonctions are f(x) equals like x +3 or x cubed for example right?
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Re: [Insert an uncreative chat room title here]

Postby VucubCaquix » Thu Apr 23, 2015 2:11 pm

totor wrote:linear fonctions are f(x) equals like x +3 or x cubed for example right?


Linear means that x is only to the power of one. So it can't be cubed or anything like that.
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Re: [Insert an uncreative chat room title here]

Postby PuppetStrings » Thu Apr 23, 2015 2:12 pm

birdyluv0 wrote:Yeah, yeah, let's talk about math.

How do you find the vertex on a parabola?
Well...
Okay, let's not get into this.

You have an equation like this y = ax² + bx + c
Do -b/2a and that will give you the point X of the vertex (being the vertex X;Y it will give you that X)
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Now replace that point in the first equation.

So, let's say that you have
y = 2x² + 4x + 12
then you do
-b/2a. That would be -4/2*2 and it's equal to -1. So the vertex is in -1;Y
Now you replace the X with -1
y = 2*(-1)² + 4*(-1) + 12 and that will give you the point Y of the vertex (in this case, 10, so the vertex is the point -1;10)
Sorry for the bad English >.<

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